Heat of Fusion of Ice

Purpose: Determine the heat of fusion of ice

Procedure:

1) Start with 100ml H2O at 50° C

2) Place into calorimeter (styrofoam cup) -record temp

3) Draw two or three ice cubes in and stir, don't run out of ice

4) Once temp stabilizes around 0°C remove ice (unmelted)

5) Measure new volume

Data: 

Calculations:

1) Mass of 100kk H2O =100g

2) Cal q= m*^t*c   =   Q= 100g * 50° C * 4.18 kj/mol

3) Determine q ice  =  16.720 kj/mol

4) Mass of ice melted = 80g H2O

5) Mole of melted ice = 4.4 mol H2O

6) ^ H of fusion for ice = 16,720/ 1000= 16.72 kj/mol

16.72/4.4 mol = 3.8 kj/mol

 

Conclusion:

Our heat of fusion was 3.8kj/mol. The final result had 36.7% error. We let the ice sit in the water for a while before we took the temperature which made a difference on the result.